Academic Team Math Practice Test 2026 - Free Math Practice Questions and Study Guide

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What is the fifth term in the binomial expansion of (x - 3y)^8?

1680x^5y^3

5670x^4y^4

To determine the fifth term in the binomial expansion of \((x - 3y)^8\), we can use the Binomial Theorem, which states that the expansion of \((a + b)^n\) can be expressed as:

\[

\sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k

\]

In this case, \(a = x\), \(b = -3y\), and \(n = 8\).

The general term in the expansion, often denoted as \(T_{k+1}\), is given by:

\[

T_{k+1} = \binom{n}{k} a^{n-k} b^k

\]

For the fifth term, we set \(k = 4\) (since we start counting from \(k = 0\)). Thus, we have:

\[

T_{5} = \binom{8}{4} (x)^{8-4} (-3y)^4

\]

Now, calculating each part:

1. **Calculate the binomial coefficient**:

\(\binom{8}{4} =

120x^6y^2

1365x^3y^5

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